It's a quiet Sunday afternoon, and I like Maths. So let's throw some maths at the problem.
Density for Norway spruce is approx 0.43t per m³. So, a 200mm diameter log of 1m length has a weight of:
((pi x 0.1 x 0.1) x 1) 0.43 = 0.0135t aka 13.5kg per linear meter. So a 10m length for one wall would be 135kg...
To make the wall 2m high, you would thus need 10 pieces of such wood. Making a 10m wall, 2m high, built from 200mm diameter logs would involve shifting 1.35 tons of wood... a full 10m x 20m cabin (ignoring roof, any internal walls, and the floor...) would come in at 1.35t x 6 = 8.1 tons. Give or take...
This is of course all purely academic and has nothing to do with any legal aspects of the idea. It's a nice thought experiment.
On a related note, if you fancy working out what this would be in Oak or Chestnut, then replace the 0.43t m³ with 0.74m³ and 0.56t m³ respectively...
Idly wondering how many trees that would be, making the assumption that each tree has 10m of usable trunk that is all 200mm diameter[1], to make a 10m x 20m cabin 2m tall, you would need 60 trees...
With one tree every 5m, and them all distributed evenly[2]... Those 60 trees would be 1500 square meters of land... ish. But then this is into the rolling of dice area of maths, as unless they are planted in a regular plantation form (meaning they are a crop and no wild and you *REALLY* *SHOULD* *NOT* cut them down, that's someone's crop), they will be more irregularly spread out than that, and for every tree suitable there is likely to be 2-3 that are not suitable...
Ok, enough maths, you get the idea. Back to the drawing board...
Julia
PS, either my maths is wrong, or Norway Spruce is considerably less dense than I thought it was.
[1]Yes that's a hell of an assumption, but it makes the maths easy and this is no exam paper, just a thought experiment.
[2]Sssh, I'm just making up numbers now, maths is fun remember...